How to print the epoch using date command

To print epoch - The seconds that has passed since 1970-01-01 00:00:00 UTC, run the following command,

date +"%s" 1480572641

Here %s tells date to print the epoch.

Tested on: CentOS 7, Debian 8, Ubuntu 16.04

Make LinuxMint 18 - Sarah USB Bootable Drive using Ubuntu

Make LinuxMint 18 - Sarah USB Bootable Drive using Ubuntu

Step 1: Go to the terminal.

Step 2: Type '   /dev/sd*   ' to see the device identifier of your usb drive. it should be something like /dev/sdb /dev/sdc. In my case it's '   /dev/sdb   '

Step 3: Type 'dd if=Location_of_Your_ISO_image.iso of=/dev/sdb bs=4096'. I have Linux Mint iso on my Downloads folder.

    sudo dd if=./Downloads/linuxmint-18-cinnamon-64bit of=/dev/sdb bs=4096  

Step 4: Wait

Step 5: Once it's done, enjoy.

You may watch how it's done on youtube. Please subscribe my channel if you do like it. :-)
Watch on YouTube